It is opposite to centripetal force.įORMULA FOR CALCULATING CENTRIFUGAL FORCE: Centrifugal force is a balancing force which counterbalances the centripetal force so as to prevent the centripetal force from pushing the object to the centre of the circle. Make V the subject: 200 * 2.10 / 34.5 = V² ➡ V² = 420 / 34.5 = 12.174Ĭentripetal acceleration = V² / r ➡ c.a = 3.49² / 2.10 = 12.18 / 2.10 = 5.80 m/s²Ĭentrifugal force is an outward force which act on an object that moves round a circle. If 200 N force act on a train of mass 34.5 kg that is moving round a circle with a velocity V, of radius 2.10 m, calculate the velocity of the train and hence what is its centripetal acceleration?ĭata: mass = 34.5 kg, velocity = V, radius = 2.10 m, force = 200N, c.a = ? Therefore, we will get, a = V² / rĬalculate the magnitude if centripetal force on a car of mass 5.23kg that is moving round a circle of radius 0.5m with a a velocity of 10m/s.Also, determine the centripetal acceleration of the object.ĭata: mass = 5.23kg, radius = 0.5m, velocity = 10 m/sį = 5.23kg * ( 10m/s )² / 0.5 ➡ F = 5.23 * 100 / 0.5 = 523 / 0.5 m = 100 / 0.5 = 1046NĬ. I f we equate equation 1 and equation 2, then we will get, Where m is the mass of the object, v is the velocity of the object, r is the radius of the circular pathįrom the formula of force, force = mass * acceleration. The force help to stop the object from skidding out of the circular path.įORMULA FOR CALCULATING CENTRIPETAL FORCE:Ĭentripetal force = m * v² /r. S = 15 m/s * 120 secondsĬentripetal force is an inward force that act on an object that is moving round a circle. Make the subject of the formula: ω = 15m/s / 0.25 m. S = 15 m/s * 1revolutionsĭata: Mass = 0.5kg, Velocity = 15m/s, radius of the circular path = 0.25m, time = 2min. We will use the formula, velocity = distance / tim, to calculate distance travelled Number of revolutions = 137496 / 360 = 381.94 revolutions We can change this 137496° to numbers of revolutions by dividing it by 360° because 360° makes 1 revolution. The angle θ which the object swept through = 137496°. Now we will convert 2400 radians to degrees by multiplying 2400 by 55.29°. Now we will calculate how many degrees make 1 radian thus:Ħ.284 rad 360°, ➡ 1 rad = 360° / 6.284. Now we have to change 2400 radians to degree.ģ60 degrees. We can not use equation 1 because the value of s is not known or given in the question. We can not use equation 1, we will use equation 2 because,the value of t is known and we have calculated ω from the calculation we did above. Write down the formula for the calculation, which is ➡Answer : angular velocity ω = 60 radian per second Now you make ω the subject of the formula. Therefore, you will get,ġ5m/s = ω * 0.25. S tep III: substitute for the data in the equation. Step II: write down the formufor the calculation, which is Mass = 0.5kg, Velocity = 15m/s, radius of the circular path = 0.25m, time = 2 minutes. Step I: you extract the data given in the question: Ω is the angular velocity of the object, measured in radian per second ( rad/s )Ī stone of mass 0.5kg is tied to one end of a rope and whirled so that it moved in a circular path of radius 0.25m with a velocity of 15m/s for 2 minutes.Ĭalculate the angular velocity of the object, angle sweep through, distance traveled. R is the radius of the circular path which the object moved round, measured in meter. V is the linear velocity of the object that is moving in a circular path, measured in m/s. Therefore, formula that connect v, r and ω is Now, you substitute for v of equation 2 in equation 4. Now, you substitute for θ of equation 1 in equation 3. Let us make θ the subject, then we will get,Īlso, recall that, angular velocity = angle / time. Relationship between linear speed and angular speed:įrom the figure above, as the stone moves round the circular path and sweep through angle®, distance S increases.ĭistance S is directly proportional to angle ®ĭistance S & angle θ.
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